Solve g(x)=4x^5+x^2/3-6

$$g ( x ) = 4 x ^ { 5 } + \frac { x ^ { 2 } } { 3 } - 6$$

Evaluate

$$4x^{5}+\frac{x^{2}}{3}-6$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 4x^{5}-6 times \frac{3}{3}.

$$\frac{3\left(4x^{5}-6\right)}{3}+\frac{x^{2}}{3}$$

Since \frac{3\left(4x^{5}-6\right)}{3} and \frac{x^{2}}{3} have the same denominator, add them by adding their numerators.

$$\frac{3\left(4x^{5}-6\right)+x^{2}}{3}$$

Do the multiplications in 3\left(4x^{5}-6\right)+x^{2}.

$$\frac{12x^{5}-18+x^{2}}{3}$$

Factor

$$\frac{12x^{5}+x^{2}-18}{3}$$

Solution Steps

Factor out \frac{1}{3}. Polynomial 12x^{5}+x^{2}-18 is not factored since it does not have any rational roots.

$$\frac{12x^{5}+x^{2}-18}{3}$$