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x\left(-x^{2}+6x-9\right)
Factor out x.
a+b=6 ab=-\left(-9\right)=9
Consider -x^{2}+6x-9. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx-9. To find a and b, set up a system to be solved.
1,9 3,3
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 9.
1+9=10 3+3=6
Calculate the sum for each pair.
a=3 b=3
The solution is the pair that gives sum 6.
\left(-x^{2}+3x\right)+\left(3x-9\right)
Rewrite -x^{2}+6x-9 as \left(-x^{2}+3x\right)+\left(3x-9\right).
-x\left(x-3\right)+3\left(x-3\right)
Factor out -x in the first and 3 in the second group.
\left(x-3\right)\left(-x+3\right)
Factor out common term x-3 by using distributive property.
x\left(x-3\right)\left(-x+3\right)
Rewrite the complete factored expression.