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4\left(-x^{5}+12x^{3}-27x\right)
Factor out 4.
x\left(-x^{4}+12x^{2}-27\right)
Consider -x^{5}+12x^{3}-27x. Factor out x.
\left(x^{2}-9\right)\left(-x^{2}+3\right)
Consider -x^{4}+12x^{2}-27. Find one factor of the form kx^{m}+n, where kx^{m} divides the monomial with the highest power -x^{4} and n divides the constant factor -27. One such factor is x^{2}-9. Factor the polynomial by dividing it by this factor.
\left(x-3\right)\left(x+3\right)
Consider x^{2}-9. Rewrite x^{2}-9 as x^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
4x\left(x-3\right)\left(x+3\right)\left(-x^{2}+3\right)
Rewrite the complete factored expression. Polynomial -x^{2}+3 is not factored since it does not have any rational roots.