Solve g(x)=-3x-11x_{0}=-3

$$g ( x ) = - 3 x - 11 x _ { 0 } = - 3$$

Solve for x

$$x=-\frac{11x_{0}}{3}+1$$

Steps for Solving Linear Equation

Add 11x_{0} to both sides.

$$-3x=-3+11x_{0}$$

The equation is in standard form.

$$-3x=11x_{0}-3$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{11x_{0}-3}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{11x_{0}-3}{-3}$$

Divide -3+11x_{0} by -3.

$$x=-\frac{11x_{0}}{3}+1$$

Solve for x_0

$$x_{0}=\frac{3-3x}{11}$$

Steps for Solving Linear Equation

Add 3x to both sides.

$$-11x_{0}=-3+3x$$

The equation is in standard form.

$$-11x_{0}=3x-3$$

Divide both sides by -11.

$$\frac{-11x_{0}}{-11}=\frac{3x-3}{-11}$$

Dividing by -11 undoes the multiplication by -11.

$$x_{0}=\frac{3x-3}{-11}$$

Divide -3+3x by -11.

$$x_{0}=\frac{3-3x}{11}$$