Solve g^2-4(8)(x)=0

$$g ^ { 2 } - 4 ( 8 ) ( x ) = 0$$

Solve for x

$$x=\frac{g^{2}}{32}$$

Steps for Solving Linear Equation

Multiply 4 and 8 to get 32.

$$g^{2}-32x=0$$

Subtract g^{2} from both sides. Anything subtracted from zero gives its negation.

$$-32x=-g^{2}$$

Divide both sides by -32.

$$\frac{-32x}{-32}=-\frac{g^{2}}{-32}$$

Dividing by -32 undoes the multiplication by -32.

$$x=-\frac{g^{2}}{-32}$$

Divide -g^{2} by -32.

$$x=\frac{g^{2}}{32}$$

Solve for g (complex solution)

$$g=-4\sqrt{2x}$$

$$g=4\sqrt{2x}$$

Solve for g

$$g=4\sqrt{2x}$$

$$g=-4\sqrt{2x}\text{, }x\geq 0$$