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g\left(g-14\right)=0
Factor out g.
g=0 g=14
To find equation solutions, solve g=0 and g-14=0.
g^{2}-14g=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
g=\frac{-\left(-14\right)±\sqrt{\left(-14\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -14 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
g=\frac{-\left(-14\right)±14}{2}
Take the square root of \left(-14\right)^{2}.
g=\frac{14±14}{2}
The opposite of -14 is 14.
g=\frac{28}{2}
Now solve the equation g=\frac{14±14}{2} when ± is plus. Add 14 to 14.
g=14
Divide 28 by 2.
g=\frac{0}{2}
Now solve the equation g=\frac{14±14}{2} when ± is minus. Subtract 14 from 14.
g=0
Divide 0 by 2.
g=14 g=0
The equation is now solved.
g^{2}-14g=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
g^{2}-14g+\left(-7\right)^{2}=\left(-7\right)^{2}
Divide -14, the coefficient of the x term, by 2 to get -7. Then add the square of -7 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
g^{2}-14g+49=49
Square -7.
\left(g-7\right)^{2}=49
Factor g^{2}-14g+49. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(g-7\right)^{2}}=\sqrt{49}
Take the square root of both sides of the equation.
g-7=7 g-7=-7
Simplify.
g=14 g=0
Add 7 to both sides of the equation.