Solve for g
g=y\left(3x+7\right)
y\neq 0
Solve for x
x=\frac{g}{3y}-\frac{7}{3}
y\neq 0
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\frac{1}{y}g=3x+7
The equation is in standard form.
\frac{\frac{1}{y}gy}{1}=\frac{\left(3x+7\right)y}{1}
Divide both sides by y^{-1}.
g=\frac{\left(3x+7\right)y}{1}
Dividing by y^{-1} undoes the multiplication by y^{-1}.
g=y\left(3x+7\right)
Divide 3x+7 by y^{-1}.
g=3xy+y\times 7
Multiply both sides of the equation by y.
3xy+y\times 7=g
Swap sides so that all variable terms are on the left hand side.
3xy=g-y\times 7
Subtract y\times 7 from both sides.
3xy=g-7y
Multiply -1 and 7 to get -7.
3yx=g-7y
The equation is in standard form.
\frac{3yx}{3y}=\frac{g-7y}{3y}
Divide both sides by 3y.
x=\frac{g-7y}{3y}
Dividing by 3y undoes the multiplication by 3y.
x=\frac{g}{3y}-\frac{7}{3}
Divide -7y+g by 3y.
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