Solve for f
f=x^{2}-2x-4+\frac{2}{x}
x\neq 0
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xf=x^{3}-2x^{2}-4x+2
The equation is in standard form.
\frac{xf}{x}=\frac{x^{3}-2x^{2}-4x+2}{x}
Divide both sides by x.
f=\frac{x^{3}-2x^{2}-4x+2}{x}
Dividing by x undoes the multiplication by x.
f=x^{2}-2x-4+\frac{2}{x}
Divide x^{3}-2x^{2}-4x+2 by x.
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