Solve for f
f=-1+\frac{3}{x}
x\neq 0
Solve for x
x=\frac{3}{f+1}
f\neq -1
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xf=3-x
The equation is in standard form.
\frac{xf}{x}=\frac{3-x}{x}
Divide both sides by x.
f=\frac{3-x}{x}
Dividing by x undoes the multiplication by x.
f=-1+\frac{3}{x}
Divide -x+3 by x.
fx+x=3
Add x to both sides.
\left(f+1\right)x=3
Combine all terms containing x.
\frac{\left(f+1\right)x}{f+1}=\frac{3}{f+1}
Divide both sides by f+1.
x=\frac{3}{f+1}
Dividing by f+1 undoes the multiplication by f+1.
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