Solve for f (complex solution)
\left\{\begin{matrix}f=\frac{3x+2}{3y}\text{, }&y\neq 0\\f\in \mathrm{C}\text{, }&x=-\frac{2}{3}\text{ and }y=0\end{matrix}\right.
Solve for f
\left\{\begin{matrix}f=\frac{3x+2}{3y}\text{, }&y\neq 0\\f\in \mathrm{R}\text{, }&x=-\frac{2}{3}\text{ and }y=0\end{matrix}\right.
Solve for x
x=fy-\frac{2}{3}
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yf=x+\frac{2}{3}
The equation is in standard form.
\frac{yf}{y}=\frac{x+\frac{2}{3}}{y}
Divide both sides by y.
f=\frac{x+\frac{2}{3}}{y}
Dividing by y undoes the multiplication by y.
yf=x+\frac{2}{3}
The equation is in standard form.
\frac{yf}{y}=\frac{x+\frac{2}{3}}{y}
Divide both sides by y.
f=\frac{x+\frac{2}{3}}{y}
Dividing by y undoes the multiplication by y.
x+\frac{2}{3}=fy
Swap sides so that all variable terms are on the left hand side.
x=fy-\frac{2}{3}
Subtract \frac{2}{3} from both sides.
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