Solve for f
f=x-2+\frac{3}{x}
x\neq 0
Solve for x (complex solution)
x=\frac{-\sqrt{f^{2}+4f-8}+f+2}{2}
x=\frac{\sqrt{f^{2}+4f-8}+f+2}{2}
Solve for x
x=\frac{-\sqrt{f^{2}+4f-8}+f+2}{2}
x=\frac{\sqrt{f^{2}+4f-8}+f+2}{2}\text{, }f\geq 2\sqrt{3}-2\text{ or }f\leq -2\sqrt{3}-2
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xf=x^{2}-2x+3
The equation is in standard form.
\frac{xf}{x}=\frac{x^{2}-2x+3}{x}
Divide both sides by x.
f=\frac{x^{2}-2x+3}{x}
Dividing by x undoes the multiplication by x.
f=x-2+\frac{3}{x}
Divide x^{2}-2x+3 by x.
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