Solve for f
f=-x-2+\frac{8}{x}
x\neq 0
Solve for x
x=\frac{\sqrt{f^{2}+4f+36}}{2}-\frac{f}{2}-1
x=-\frac{\sqrt{f^{2}+4f+36}}{2}-\frac{f}{2}-1
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xf=8-2x-x^{2}
The equation is in standard form.
\frac{xf}{x}=\frac{\left(2-x\right)\left(x+4\right)}{x}
Divide both sides by x.
f=\frac{\left(2-x\right)\left(x+4\right)}{x}
Dividing by x undoes the multiplication by x.
f=-x-2+\frac{8}{x}
Divide \left(2-x\right)\left(4+x\right) by x.
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