Solve for f
f=-2x+2-\frac{1}{x}
x\neq 0
Solve for x (complex solution)
x=\frac{\sqrt{f^{2}-4f-4}}{4}-\frac{f}{4}+\frac{1}{2}
x=-\frac{\sqrt{f^{2}-4f-4}}{4}-\frac{f}{4}+\frac{1}{2}
Solve for x
x=\frac{\sqrt{f^{2}-4f-4}}{4}-\frac{f}{4}+\frac{1}{2}
x=-\frac{\sqrt{f^{2}-4f-4}}{4}-\frac{f}{4}+\frac{1}{2}\text{, }f\geq 2\sqrt{2}+2\text{ or }f\leq 2-2\sqrt{2}
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xf=-2x^{2}+2x-1
The equation is in standard form.
\frac{xf}{x}=\frac{-2x^{2}+2x-1}{x}
Divide both sides by x.
f=\frac{-2x^{2}+2x-1}{x}
Dividing by x undoes the multiplication by x.
f=-2x+2-\frac{1}{x}
Divide -2x^{2}+2x-1 by x.
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