Solve f_{2}(x)=4cos(x-0,5pi)

$$f _ { 2 } ( x ) = 4 \cos ( x - 0,5 \pi )$$

Solve for f_2

$$\left\{\begin{matrix}f_{2}=\frac{4\cos(x-\frac{\pi }{2})}{x}\text{, }&x\neq 0\\f_{2}\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$xf_{2}=4\cos(x-\frac{\pi }{2})$$

Divide both sides by x.

$$\frac{xf_{2}}{x}=\frac{4\cos(x-\frac{\pi }{2})}{x}$$

Dividing by x undoes the multiplication by x.

$$f_{2}=\frac{4\cos(x-\frac{\pi }{2})}{x}$$

Divide 4\cos(x-\frac{\pi }{2}) by x.

$$f_{2}=\frac{4\cos(\frac{2x-\pi }{2})}{x}$$