Solve f3-2(p+1)=p-2p

$$f 3 - 2 ( p + 1 ) = p - 2 p$$

Solve for f_3

$$f_{3}=p+2$$

Solution Steps

Use the distributive property to multiply -2 by p+1.

$$f_{3}-2p-2=p-2p$$

Combine p and -2p to get -p.

$$f_{3}-2p-2=-p$$

Add 2p to both sides.

$$f_{3}-2=-p+2p$$

Combine -p and 2p to get p.

$$f_{3}-2=p$$

Add 2 to both sides.

$$f_{3}=p+2$$

Solve for p

$$p=f_{3}-2$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2 by p+1.

$$f_{3}-2p-2=p-2p$$

Combine p and -2p to get -p.

$$f_{3}-2p-2=-p$$

Add p to both sides.

$$f_{3}-2p-2+p=0$$

Combine -2p and p to get -p.

$$f_{3}-p-2=0$$

Subtract f_{3} from both sides. Anything subtracted from zero gives its negation.

$$-p-2=-f_{3}$$

Add 2 to both sides.

$$-p=-f_{3}+2$$

The equation is in standard form.

$$-p=2-f_{3}$$

Divide both sides by -1.

$$\frac{-p}{-1}=\frac{2-f_{3}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$p=\frac{2-f_{3}}{-1}$$

Divide -f_{3}+2 by -1.

$$p=f_{3}-2$$