Solve f3(x+6)=39

$$f 3 ( x + 6 ) = 39$$

Solve for f_3

$$f_{3}=\frac{39}{x+6}$$

$$x\neq -6$$

Steps for Solving Linear Equation

Use the distributive property to multiply f_{3} by x+6.

$$f_{3}x+6f_{3}=39$$

Combine all terms containing f_{3}.

$$\left(x+6\right)f_{3}=39$$

Divide both sides by x+6.

$$\frac{\left(x+6\right)f_{3}}{x+6}=\frac{39}{x+6}$$

Dividing by x+6 undoes the multiplication by x+6.

$$f_{3}=\frac{39}{x+6}$$

Solve for x

$$x=-6+\frac{39}{f_{3}}$$

$$f_{3}\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply f_{3} by x+6.

$$f_{3}x+6f_{3}=39$$

Subtract 6f_{3} from both sides.

$$f_{3}x=39-6f_{3}$$

Divide both sides by f_{3}.

$$\frac{f_{3}x}{f_{3}}=\frac{39-6f_{3}}{f_{3}}$$

Dividing by f_{3} undoes the multiplication by f_{3}.

$$x=\frac{39-6f_{3}}{f_{3}}$$

Divide 39-6f_{3} by f_{3}.

$$x=-6+\frac{39}{f_{3}}$$