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x^{4}-3x^{3}-3x^{2}-75x-700=0
To factor the expression, solve the equation where it equals to 0.
±700,±350,±175,±140,±100,±70,±50,±35,±28,±25,±20,±14,±10,±7,±5,±4,±2,±1
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -700 and q divides the leading coefficient 1. List all candidates \frac{p}{q}.
x=-4
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
x^{3}-7x^{2}+25x-175=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide x^{4}-3x^{3}-3x^{2}-75x-700 by x+4 to get x^{3}-7x^{2}+25x-175. To factor the result, solve the equation where it equals to 0.
±175,±35,±25,±7,±5,±1
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -175 and q divides the leading coefficient 1. List all candidates \frac{p}{q}.
x=7
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
x^{2}+25=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide x^{3}-7x^{2}+25x-175 by x-7 to get x^{2}+25. To factor the result, solve the equation where it equals to 0.
x=\frac{0±\sqrt{0^{2}-4\times 1\times 25}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 0 for b, and 25 for c in the quadratic formula.
x=\frac{0±\sqrt{-100}}{2}
Do the calculations.
x^{2}+25
Polynomial x^{2}+25 is not factored since it does not have any rational roots.
\left(x-7\right)\left(x+4\right)\left(x^{2}+25\right)
Rewrite the factored expression using the obtained roots.