Solve for g
g=\frac{x^{3}-3}{3x}
x\neq 0
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-3gx=3-x^{3}
Subtract x^{3} from both sides.
\left(-3x\right)g=3-x^{3}
The equation is in standard form.
\frac{\left(-3x\right)g}{-3x}=\frac{3-x^{3}}{-3x}
Divide both sides by -3x.
g=\frac{3-x^{3}}{-3x}
Dividing by -3x undoes the multiplication by -3x.
g=\frac{x^{2}}{3}-\frac{1}{x}
Divide 3-x^{3} by -3x.
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