Solve for g
g=-\frac{x}{4}+\frac{1}{2}+\frac{3}{4x}
x\neq 0
Solve for x
x=2\sqrt{g^{2}-g+1}-2g+1
x=-2\sqrt{g^{2}-g+1}-2g+1
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4gx=2x+3-x^{2}
Subtract x^{2} from both sides.
4xg=3+2x-x^{2}
The equation is in standard form.
\frac{4xg}{4x}=-\frac{\left(x-3\right)\left(x+1\right)}{4x}
Divide both sides by 4x.
g=-\frac{\left(x-3\right)\left(x+1\right)}{4x}
Dividing by 4x undoes the multiplication by 4x.
g=-\frac{x}{4}+\frac{1}{2}+\frac{3}{4x}
Divide -\left(-3+x\right)\left(1+x\right) by 4x.
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y = 3x + 4
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Simultaneous equation
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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