Solve for f
f=\frac{e^{x}\left(e^{2x}-6\right)}{x}
x\neq 0
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fx=e^{3x}-6e^{x}
Multiply -1 and 6 to get -6.
xf=e^{3x}-6e^{x}
The equation is in standard form.
\frac{xf}{x}=\frac{e^{x}\left(e^{2x}-6\right)}{x}
Divide both sides by x.
f=\frac{e^{x}\left(e^{2x}-6\right)}{x}
Dividing by x undoes the multiplication by x.
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