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Solve for f
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fx=e^{\frac{\mathrm{d}}{\mathrm{d}x}(0)\times 25x^{2}-5\frac{\mathrm{d}}{\mathrm{d}x}(0)x+1}
Multiply -1 and 5 to get -5.
xf=e
The equation is in standard form.
\frac{xf}{x}=\frac{e}{x}
Divide both sides by x.
f=\frac{e}{x}
Dividing by x undoes the multiplication by x.