f ( x ) = e ^ { - 0,5 x }
Solve for f
f=\frac{e^{-\frac{x}{2}}}{x}
x\neq 0
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xf=e^{-\frac{x}{2}}
The equation is in standard form.
\frac{xf}{x}=\frac{e^{-\frac{x}{2}}}{x}
Divide both sides by x.
f=\frac{e^{-\frac{x}{2}}}{x}
Dividing by x undoes the multiplication by x.
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