Solve for g
g=\frac{x-2}{x}
x\neq 0
Solve for x
x=\frac{2}{1-g}
g\neq 1
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-3gx=3x+6-6x
Subtract 6x from both sides.
-3gx=-3x+6
Combine 3x and -6x to get -3x.
\left(-3x\right)g=6-3x
The equation is in standard form.
\frac{\left(-3x\right)g}{-3x}=\frac{6-3x}{-3x}
Divide both sides by -3x.
g=\frac{6-3x}{-3x}
Dividing by -3x undoes the multiplication by -3x.
g=1-\frac{2}{x}
Divide -3x+6 by -3x.
6x-3gx-3x=6
Subtract 3x from both sides.
3x-3gx=6
Combine 6x and -3x to get 3x.
\left(3-3g\right)x=6
Combine all terms containing x.
\frac{\left(3-3g\right)x}{3-3g}=\frac{6}{3-3g}
Divide both sides by -3g+3.
x=\frac{6}{3-3g}
Dividing by -3g+3 undoes the multiplication by -3g+3.
x=\frac{2}{1-g}
Divide 6 by -3g+3.
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