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3\left(2x^{3}+5x^{2}+8x+20\right)
Factor out 3.
x^{2}\left(2x+5\right)+4\left(2x+5\right)
Consider 2x^{3}+5x^{2}+8x+20. Do the grouping 2x^{3}+5x^{2}+8x+20=\left(2x^{3}+5x^{2}\right)+\left(8x+20\right), and factor out x^{2} in the first and 4 in the second group.
\left(2x+5\right)\left(x^{2}+4\right)
Factor out common term 2x+5 by using distributive property.
3\left(2x+5\right)\left(x^{2}+4\right)
Rewrite the complete factored expression. Polynomial x^{2}+4 is not factored since it does not have any rational roots.