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Solve for f, x
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9x-x=3
Consider the second equation. Subtract x from both sides.
8x=3
Combine 9x and -x to get 8x.
x=\frac{3}{8}
Divide both sides by 8.
f\times \frac{3}{8}=4\times \frac{3}{8}-6
Consider the first equation. Insert the known values of variables into the equation.
f\times \frac{3}{8}=\frac{3}{2}-6
Multiply 4 and \frac{3}{8} to get \frac{3}{2}.
f\times \frac{3}{8}=-\frac{9}{2}
Subtract 6 from \frac{3}{2} to get -\frac{9}{2}.
f=-\frac{9}{2}\times \frac{8}{3}
Multiply both sides by \frac{8}{3}, the reciprocal of \frac{3}{8}.
f=-12
Multiply -\frac{9}{2} and \frac{8}{3} to get -12.
f=-12 x=\frac{3}{8}
The system is now solved.