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\left(2x-3\right)\left(2x^{2}-9x+4\right)
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -12 and q divides the leading coefficient 4. One such root is \frac{3}{2}. Factor the polynomial by dividing it by 2x-3.
a+b=-9 ab=2\times 4=8
Consider 2x^{2}-9x+4. Factor the expression by grouping. First, the expression needs to be rewritten as 2x^{2}+ax+bx+4. To find a and b, set up a system to be solved.
-1,-8 -2,-4
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 8.
-1-8=-9 -2-4=-6
Calculate the sum for each pair.
a=-8 b=-1
The solution is the pair that gives sum -9.
\left(2x^{2}-8x\right)+\left(-x+4\right)
Rewrite 2x^{2}-9x+4 as \left(2x^{2}-8x\right)+\left(-x+4\right).
2x\left(x-4\right)-\left(x-4\right)
Factor out 2x in the first and -1 in the second group.
\left(x-4\right)\left(2x-1\right)
Factor out common term x-4 by using distributive property.
\left(x-4\right)\left(2x-3\right)\left(2x-1\right)
Rewrite the complete factored expression.