Solve f(x)=4(-2)^3-2(-2)^2+3(-2)-2

$$f ( x ) = 4 ( - 2 ) ^ { 3 } - 2 ( - 2 ) ^ { 2 } + 3 ( - 2 ) - 2$$

Evaluate

$$-48$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$4\left(-8\right)-2\left(-2\right)^{2}+3\left(-2\right)-2$$

Multiply 4 and -8 to get -32.

$$-32-2\left(-2\right)^{2}+3\left(-2\right)-2$$

Calculate -2 to the power of 2 and get 4.

$$-32-2\times 4+3\left(-2\right)-2$$

Multiply 2 and 4 to get 8.

$$-32-8+3\left(-2\right)-2$$

Subtract 8 from -32 to get -40.

$$-40+3\left(-2\right)-2$$

Multiply 3 and -2 to get -6.

$$-40-6-2$$

Subtract 6 from -40 to get -46.

$$-46-2$$

Subtract 2 from -46 to get -48.

$$-48$$

Factor

$$-48$$