Solve for f, x
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f\times 10=3\times 10-5
Consider the first equation. Insert the known values of variables into the equation.
f\times 10=30-5
Multiply 3 and 10 to get 30.
f\times 10=25
Subtract 5 from 30 to get 25.
f=\frac{25}{10}
Divide both sides by 10.
f=\frac{5}{2}
Reduce the fraction \frac{25}{10} to lowest terms by extracting and canceling out 5.
f=\frac{5}{2} x=10
The system is now solved.