Solve f(x)=3x^2-x+2,d

$$f ( x ) = 3 x ^ { 2 } - x + 2 , d$$

Solve for f

$$f=3x-1+\frac{2}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$xf=3x^{2}-x+2$$

Divide both sides by x.

$$\frac{xf}{x}=\frac{3x^{2}-x+2}{x}$$

Dividing by x undoes the multiplication by x.

$$f=\frac{3x^{2}-x+2}{x}$$

Divide 3x^{2}-x+2 by x.

$$f=3x-1+\frac{2}{x}$$

Solve for x (complex solution)

$$x=\frac{-\sqrt{f^{2}+2f-23}+f+1}{6}$$

$$x=\frac{\sqrt{f^{2}+2f-23}+f+1}{6}$$

Solve for x

$$x=\frac{-\sqrt{f^{2}+2f-23}+f+1}{6}$$

$$x=\frac{\sqrt{f^{2}+2f-23}+f+1}{6}\text{, }f\geq 2\sqrt{6}-1\text{ or }f\leq -2\sqrt{6}-1$$