Solve f(x)=3(9/5)^2-2(9/5)+5

$$f ( x ) = 3 ( 9 / 5 ) ^ { 2 } - 2 ( 9 / 5 ) + 5$$

Evaluate

$$\frac{278}{25}=11.12$$

Solution Steps

Calculate \frac{9}{5} to the power of 2 and get \frac{81}{25}.

$$3\times \frac{81}{25}-2\times \frac{9}{5}+5$$

Express 3\times \frac{81}{25} as a single fraction.

$$\frac{3\times 81}{25}-2\times \frac{9}{5}+5$$

Multiply 3 and 81 to get 243.

$$\frac{243}{25}-2\times \frac{9}{5}+5$$

Express 2\times \frac{9}{5} as a single fraction.

$$\frac{243}{25}-\frac{2\times 9}{5}+5$$

Multiply 2 and 9 to get 18.

$$\frac{243}{25}-\frac{18}{5}+5$$

Least common multiple of 25 and 5 is 25. Convert \frac{243}{25} and \frac{18}{5} to fractions with denominator 25.

$$\frac{243}{25}-\frac{90}{25}+5$$

Since \frac{243}{25} and \frac{90}{25} have the same denominator, subtract them by subtracting their numerators.

$$\frac{243-90}{25}+5$$

Subtract 90 from 243 to get 153.

$$\frac{153}{25}+5$$

Convert 5 to fraction \frac{125}{25}.

$$\frac{153}{25}+\frac{125}{25}$$

Since \frac{153}{25} and \frac{125}{25} have the same denominator, add them by adding their numerators.

$$\frac{153+125}{25}$$

Add 153 and 125 to get 278.

$$\frac{278}{25}$$

Factor

$$\frac{2 \cdot 139}{5 ^ {2}} = 11\frac{3}{25} = 11.12$$