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2\left(x^{3}+6x-5x^{2}\right)
Factor out 2.
x\left(x^{2}+6-5x\right)
Consider x^{3}+6x-5x^{2}. Factor out x.
x^{2}-5x+6
Consider x^{2}+6-5x. Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=-5 ab=1\times 6=6
Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+6. To find a and b, set up a system to be solved.
-1,-6 -2,-3
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 6.
-1-6=-7 -2-3=-5
Calculate the sum for each pair.
a=-3 b=-2
The solution is the pair that gives sum -5.
\left(x^{2}-3x\right)+\left(-2x+6\right)
Rewrite x^{2}-5x+6 as \left(x^{2}-3x\right)+\left(-2x+6\right).
x\left(x-3\right)-2\left(x-3\right)
Factor out x in the first and -2 in the second group.
\left(x-3\right)\left(x-2\right)
Factor out common term x-3 by using distributive property.
2x\left(x-3\right)\left(x-2\right)
Rewrite the complete factored expression.