Solve for f, x
x=1
f=3
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f\times 1=1+1+|1|
Consider the first equation. Insert the known values of variables into the equation.
f\times 1=2+|1|
Add 1 and 1 to get 2.
f\times 1=2+1
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 1 is 1.
f\times 1=3
Add 2 and 1 to get 3.
f=3
Divide both sides by 1.
f=3 x=1
The system is now solved.
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