Solve f(x)=1+frac{sqrt{3}}{3}x

$$f ( x ) = 1 + \frac { \sqrt { 3 } } { 3 } x$$

Evaluate

$$\frac{\sqrt{3}x}{3}+1$$

Short Solution Steps

Express \frac{\sqrt{3}}{3}x as a single fraction.

$$1+\frac{\sqrt{3}x}{3}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{3}{3}.

$$\frac{3}{3}+\frac{\sqrt{3}x}{3}$$

Since \frac{3}{3} and \frac{\sqrt{3}x}{3} have the same denominator, add them by adding their numerators.

$$\frac{3+\sqrt{3}x}{3}$$

Factor

$$\frac{\sqrt{3}\left(x+\sqrt{3}\right)}{3}$$

Solution Steps

Factor out \frac{1}{3}.

$$\frac{3+\sqrt{3}x}{3}$$

Consider 3+\sqrt{3}x. Factor out \sqrt{3}.

$$\sqrt{3}\left(\sqrt{3}+x\right)$$

Rewrite the complete factored expression.

$$\frac{\sqrt{3}\left(\sqrt{3}+x\right)}{3}$$