Solve f(x)=-5-3x^2+1/x^4

$$f ( x ) = - 5 - 3 x ^ { 2 } + \frac { 1 } { x ^ { 4 } }$$

Evaluate

$$-3x^{2}-5+\frac{1}{x^{4}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply -5-3x^{2} times \frac{x^{4}}{x^{4}}.

$$\frac{\left(-5-3x^{2}\right)x^{4}}{x^{4}}+\frac{1}{x^{4}}$$

Since \frac{\left(-5-3x^{2}\right)x^{4}}{x^{4}} and \frac{1}{x^{4}} have the same denominator, add them by adding their numerators.

$$\frac{\left(-5-3x^{2}\right)x^{4}+1}{x^{4}}$$

Do the multiplications in \left(-5-3x^{2}\right)x^{4}+1.

$$\frac{-5x^{4}-3x^{6}+1}{x^{4}}$$

Factor

$$-\frac{3x^{6}+5x^{4}-1}{x^{4}}$$