Solve for g
g=-\frac{2x^{2}}{5}+\frac{2}{5}-\frac{4}{5x}
x\neq 0
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-5gx=-2x+4+2x^{3}
Add 2x^{3} to both sides.
\left(-5x\right)g=2x^{3}-2x+4
The equation is in standard form.
\frac{\left(-5x\right)g}{-5x}=\frac{2x^{3}-2x+4}{-5x}
Divide both sides by -5x.
g=\frac{2x^{3}-2x+4}{-5x}
Dividing by -5x undoes the multiplication by -5x.
g=-\frac{2x^{2}}{5}+\frac{2}{5}-\frac{4}{5x}
Divide -2x+4+2x^{3} by -5x.
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