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2\left(-x^{3}-2x^{2}+8x\right)
Factor out 2.
x\left(-x^{2}-2x+8\right)
Consider -x^{3}-2x^{2}+8x. Factor out x.
a+b=-2 ab=-8=-8
Consider -x^{2}-2x+8. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+8. To find a and b, set up a system to be solved.
1,-8 2,-4
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -8.
1-8=-7 2-4=-2
Calculate the sum for each pair.
a=2 b=-4
The solution is the pair that gives sum -2.
\left(-x^{2}+2x\right)+\left(-4x+8\right)
Rewrite -x^{2}-2x+8 as \left(-x^{2}+2x\right)+\left(-4x+8\right).
x\left(-x+2\right)+4\left(-x+2\right)
Factor out x in the first and 4 in the second group.
\left(-x+2\right)\left(x+4\right)
Factor out common term -x+2 by using distributive property.
2x\left(-x+2\right)\left(x+4\right)
Rewrite the complete factored expression.