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2\left(-x^{3}+x^{2}+6x\right)
Factor out 2.
x\left(-x^{2}+x+6\right)
Consider -x^{3}+x^{2}+6x. Factor out x.
a+b=1 ab=-6=-6
Consider -x^{2}+x+6. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+6. To find a and b, set up a system to be solved.
-1,6 -2,3
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -6.
-1+6=5 -2+3=1
Calculate the sum for each pair.
a=3 b=-2
The solution is the pair that gives sum 1.
\left(-x^{2}+3x\right)+\left(-2x+6\right)
Rewrite -x^{2}+x+6 as \left(-x^{2}+3x\right)+\left(-2x+6\right).
-x\left(x-3\right)-2\left(x-3\right)
Factor out -x in the first and -2 in the second group.
\left(x-3\right)\left(-x-2\right)
Factor out common term x-3 by using distributive property.
2x\left(x-3\right)\left(-x-2\right)
Rewrite the complete factored expression.