Solve f(x)=-2x^2-6x+8f(x)=-2x^2-6x+8

$$f ( x ) = - 2 x ^ { 2 } - 6 x + 8 f ( x ) = - 2 x ^ { 2 } - 6 x + 8$$

Solve for f

$$f=\frac{1}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Add 2x^{2} to both sides.

$$-6x+8fx=-2x^{2}-6x+8+2x^{2}$$

Combine -2x^{2} and 2x^{2} to get 0.

$$-6x+8fx=-6x+8$$

Add 6x to both sides.

$$8fx=-6x+8+6x$$

Combine -6x and 6x to get 0.

$$8fx=8$$

The equation is in standard form.

$$8xf=8$$

Divide both sides by 8x.

$$\frac{8xf}{8x}=\frac{8}{8x}$$

Dividing by 8x undoes the multiplication by 8x.

$$f=\frac{8}{8x}$$

Divide 8 by 8x.

$$f=\frac{1}{x}$$

Solve for x

$$x=\frac{1}{f}$$

$$f\neq 0$$

Steps for Solving Linear Equation

Add 2x^{2} to both sides.

$$-2x^{2}-6x+8fx+2x^{2}=-6x+8$$

Combine -2x^{2} and 2x^{2} to get 0.

$$-6x+8fx=-6x+8$$

Add 6x to both sides.

$$-6x+8fx+6x=8$$

Combine -6x and 6x to get 0.

$$8fx=8$$

Divide both sides by 8f.

$$\frac{8fx}{8f}=\frac{8}{8f}$$

Dividing by 8f undoes the multiplication by 8f.

$$x=\frac{8}{8f}$$

Divide 8 by 8f.

$$x=\frac{1}{f}$$