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\frac{3\left(-x^{2}+4x+5\right)}{5}
Factor out \frac{3}{5}.
a+b=4 ab=-5=-5
Consider -x^{2}+4x+5. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+5. To find a and b, set up a system to be solved.
a=5 b=-1
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.
\left(-x^{2}+5x\right)+\left(-x+5\right)
Rewrite -x^{2}+4x+5 as \left(-x^{2}+5x\right)+\left(-x+5\right).
-x\left(x-5\right)-\left(x-5\right)
Factor out -x in the first and -1 in the second group.
\left(x-5\right)\left(-x-1\right)
Factor out common term x-5 by using distributive property.
\frac{3\left(x-5\right)\left(-x-1\right)}{5}
Rewrite the complete factored expression.