Factor
\frac{\left(6-x\right)\left(x+8\right)}{2}
Evaluate
\frac{\left(6-x\right)\left(x+8\right)}{2}
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\frac{-x^{2}-2x+48}{2}
Factor out \frac{1}{2}.
a+b=-2 ab=-48=-48
Consider -x^{2}-2x+48. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+48. To find a and b, set up a system to be solved.
1,-48 2,-24 3,-16 4,-12 6,-8
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -48.
1-48=-47 2-24=-22 3-16=-13 4-12=-8 6-8=-2
Calculate the sum for each pair.
a=6 b=-8
The solution is the pair that gives sum -2.
\left(-x^{2}+6x\right)+\left(-8x+48\right)
Rewrite -x^{2}-2x+48 as \left(-x^{2}+6x\right)+\left(-8x+48\right).
x\left(-x+6\right)+8\left(-x+6\right)
Factor out x in the first and 8 in the second group.
\left(-x+6\right)\left(x+8\right)
Factor out common term -x+6 by using distributive property.
\frac{\left(-x+6\right)\left(x+8\right)}{2}
Rewrite the complete factored expression.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}