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\frac{-x^{2}+4x-4}{2}
Factor out \frac{1}{2}.
a+b=4 ab=-\left(-4\right)=4
Consider -x^{2}+4x-4. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx-4. To find a and b, set up a system to be solved.
1,4 2,2
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 4.
1+4=5 2+2=4
Calculate the sum for each pair.
a=2 b=2
The solution is the pair that gives sum 4.
\left(-x^{2}+2x\right)+\left(2x-4\right)
Rewrite -x^{2}+4x-4 as \left(-x^{2}+2x\right)+\left(2x-4\right).
-x\left(x-2\right)+2\left(x-2\right)
Factor out -x in the first and 2 in the second group.
\left(x-2\right)\left(-x+2\right)
Factor out common term x-2 by using distributive property.
\frac{\left(x-2\right)\left(-x+2\right)}{2}
Rewrite the complete factored expression.