Evaluate
\left(x+3\right)^{2}-2
Expand
x^{2}+6x+7
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x^{2}+6x+9-2
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
x^{2}+6x+7
Subtract 2 from 9 to get 7.
x^{2}+6x+9-2
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
x^{2}+6x+7
Subtract 2 from 9 to get 7.
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