Evaluate
\left(x+3\right)^{2}+4
Expand
x^{2}+6x+13
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x^{2}+6x+9+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
x^{2}+6x+13
Add 9 and 4 to get 13.
x^{2}+6x+9+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
x^{2}+6x+13
Add 9 and 4 to get 13.
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