Evaluate
2\left(\sqrt{3}+2\right)\approx 7.464101615
Expand
2 \sqrt{3} + 4 = 7.464101615
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1+2\sqrt{3}+\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(1+\sqrt{3}\right)^{2}.
1+2\sqrt{3}+3
The square of \sqrt{3} is 3.
4+2\sqrt{3}
Add 1 and 3 to get 4.
1+2\sqrt{3}+\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(1+\sqrt{3}\right)^{2}.
1+2\sqrt{3}+3
The square of \sqrt{3} is 3.
4+2\sqrt{3}
Add 1 and 3 to get 4.
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