Solve for f
f=\frac{\sqrt[3]{\alpha x^{2}+2x\alpha -4x+1}}{x}
x\neq 0
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fx=\sqrt[3]{\alpha x^{2}+\left(2\alpha -4\right)x+1}
Use the distributive property to multiply 2 by \alpha -2.
fx=\sqrt[3]{\alpha x^{2}+2\alpha x-4x+1}
Use the distributive property to multiply 2\alpha -4 by x.
xf=\sqrt[3]{\alpha x^{2}+2x\alpha -4x+1}
The equation is in standard form.
\frac{xf}{x}=\frac{\sqrt[3]{\alpha x^{2}+2x\alpha -4x+1}}{x}
Divide both sides by x.
f=\frac{\sqrt[3]{\alpha x^{2}+2x\alpha -4x+1}}{x}
Dividing by x undoes the multiplication by x.
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