Solve f(x)=2-3x^5/2x^3,x

$$f ( x ) = \frac { 2 - 3 x ^ { 5 } } { 2 x ^ { 3 } } , x$$

Solve for f

$$f=-\frac{3x}{2}+\frac{1}{x^{4}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2x^{3}.

$$fx\times 2x^{3}=2-3x^{5}$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$fx^{4}\times 2=2-3x^{5}$$

The equation is in standard form.

$$2x^{4}f=2-3x^{5}$$

Divide both sides by 2x^{4}.

$$\frac{2x^{4}f}{2x^{4}}=\frac{2-3x^{5}}{2x^{4}}$$

Dividing by 2x^{4} undoes the multiplication by 2x^{4}.

$$f=\frac{2-3x^{5}}{2x^{4}}$$

Divide 2-3x^{5} by 2x^{4}.

$$f=-\frac{3x}{2}+\frac{1}{x^{4}}$$