Solve f(x)=2/x^2+1+3/x^2

$$f ( x ) = \frac { 2 } { x ^ { 2 } } + 1 + \frac { 3 } { x ^ { 2 } }$$

Evaluate

$$1+\frac{5}{x^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x^{2}}{x^{2}}.

$$\frac{2}{x^{2}}+\frac{x^{2}}{x^{2}}+\frac{3}{x^{2}}$$

Since \frac{2}{x^{2}} and \frac{x^{2}}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{2+x^{2}}{x^{2}}+\frac{3}{x^{2}}$$

Since \frac{2+x^{2}}{x^{2}} and \frac{3}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{2+x^{2}+3}{x^{2}}$$

Combine like terms in 2+x^{2}+3.

$$\frac{5+x^{2}}{x^{2}}$$

Factor

$$\frac{x^{2}+5}{x^{2}}$$