Solve for f
f=-\frac{2}{3}+\frac{1}{3x}
x\neq 0
Solve for x
x=\frac{1}{3f+2}
f\neq -\frac{2}{3}
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3fx=1-2x
Multiply both sides of the equation by 3.
3xf=1-2x
The equation is in standard form.
\frac{3xf}{3x}=\frac{1-2x}{3x}
Divide both sides by 3x.
f=\frac{1-2x}{3x}
Dividing by 3x undoes the multiplication by 3x.
f=-\frac{2}{3}+\frac{1}{3x}
Divide 1-2x by 3x.
3fx=1-2x
Multiply both sides of the equation by 3.
3fx+2x=1
Add 2x to both sides.
\left(3f+2\right)x=1
Combine all terms containing x.
\frac{\left(3f+2\right)x}{3f+2}=\frac{1}{3f+2}
Divide both sides by 3f+2.
x=\frac{1}{3f+2}
Dividing by 3f+2 undoes the multiplication by 3f+2.
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