Solve f(x)=1-2x^2-4x^3/2x+3

$$f ( x ) = \frac { 1 - 2 x ^ { 2 } - 4 x ^ { 3 } } { 2 x } + 3$$

Evaluate

$$-2x^{2}-x+3+\frac{1}{2x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{2x}{2x}.

$$\frac{1-2x^{2}-4x^{3}}{2x}+\frac{3\times 2x}{2x}$$

Since \frac{1-2x^{2}-4x^{3}}{2x} and \frac{3\times 2x}{2x} have the same denominator, add them by adding their numerators.

$$\frac{1-2x^{2}-4x^{3}+3\times 2x}{2x}$$

Do the multiplications in 1-2x^{2}-4x^{3}+3\times 2x.

$$\frac{1-2x^{2}-4x^{3}+6x}{2x}$$

Expand

$$-2x^{2}-x+3+\frac{1}{2x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{2x}{2x}.

$$\frac{1-2x^{2}-4x^{3}}{2x}+\frac{3\times 2x}{2x}$$

Since \frac{1-2x^{2}-4x^{3}}{2x} and \frac{3\times 2x}{2x} have the same denominator, add them by adding their numerators.

$$\frac{1-2x^{2}-4x^{3}+3\times 2x}{2x}$$

Do the multiplications in 1-2x^{2}-4x^{3}+3\times 2x.

$$\frac{1-2x^{2}-4x^{3}+6x}{2x}$$