Solve for y (complex solution)
\left\{\begin{matrix}\\y=0\text{, }&\text{unconditionally}\\y\in \mathrm{C}\text{, }&x=2\end{matrix}\right.
Solve for y
\left\{\begin{matrix}\\y=0\text{, }&\text{unconditionally}\\y\in \mathrm{R}\text{, }&x=2\end{matrix}\right.
Solve for x (complex solution)
\left\{\begin{matrix}\\x=2\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&y=0\end{matrix}\right.
Solve for x
\left\{\begin{matrix}\\x=2\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&y=0\end{matrix}\right.
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\frac{1}{3}\left(x^{2}-4x+4\right)y=0
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
\left(\frac{1}{3}x^{2}-\frac{4}{3}x+\frac{4}{3}\right)y=0
Use the distributive property to multiply \frac{1}{3} by x^{2}-4x+4.
\frac{x^{2}-4x+4}{3}y=0
The equation is in standard form.
y=0
Divide 0 by \frac{1}{3}x^{2}-\frac{4}{3}x+\frac{4}{3}.
\frac{1}{3}\left(x^{2}-4x+4\right)y=0
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
\left(\frac{1}{3}x^{2}-\frac{4}{3}x+\frac{4}{3}\right)y=0
Use the distributive property to multiply \frac{1}{3} by x^{2}-4x+4.
\frac{x^{2}-4x+4}{3}y=0
The equation is in standard form.
y=0
Divide 0 by \frac{1}{3}x^{2}-\frac{4}{3}x+\frac{4}{3}.
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